[SOLVED] Illegal Number - Shell Script

Issue

My code was working fine then the next day I get

./Desktop/audiolog.sh: 32: [: /proc/: unexpected operator

./Desktop/audiolog.sh: 13: ./Desktop/audiolog.sh: Illegal number: 08

Is it perhaps the number 08 within the seconds? Any pointers will be great thanks

#!/bin/sh  

DAY=$(date +%d)                          
MO=$(date +%m)                             
YR=$(date +%y)                 
SE=$(date +%S)                             
H=$(date +%H)                                                           
M=$(date +%M)  

NOW=$(date)

DURATION=$(((60 - M) * 60-SE))

PART=$(find /mnt/hgfs/Audio\ Log/ -type f -name "RBLoggerAudio ${DAY}-${MO}-${YR}\ ${H}*" | wc -l)

reset

echo "Recording for $DAY $MO $YR - $H 00"
echo "Started at $NOW"
echo "- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -"

if [ "$PART" -eq 0 ]
then
    arecord -f cd -c 1 -d$DURATION -t raw -v -v | lame -b 64 -q8 -mm -r - /mnt/hgfs/Audio\ Log/"RBLoggerAudio "$DAY-$MO-$YR\ $H"00".mp3    
else
    arecord -f cd -c 1 -d$DURATION -t raw -v -v | lame -b 64 -q8 -mm -r - /mnt/hgfs/Audio\ Log/"RBLoggerAudio "$DAY-$MO-$YR\ $H"00 - Part - "$PART.mp3
fi


pid=$(ps -opid= -C audiolog.sh)
while [ -d /proc/$pid ] ; do
    sleep 1
done && ./Desktop/audiolog.sh

Solution

Change this

while [ -d /proc/$pid ] ; do

with

while [ -d "/proc/$pid" ] ; do

Answered By - Skynet